MCAT Question A Day - 8/18/13 - Answer!
What is the current in the circuit shown below?
A. 0.5 A
B. 2.0 A
C. 6.0 A
D. 12 A
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The correct answer is (B). The three resistors are connected in series so R(tot) = Sum(R) = 6 V. From Ohm’s law, V(tot) / R(tot) = I(tot) = 12V / 6V = 2A.
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