Practice MCAT Question - Q49 - Answer!
What is the magnitude of the force acting on a particle of charge 1C traveling with a velocity of 1 m/s in a direction parallel to a magnetic field of 1 T?
A. 0 N
B. 0.5 N
C. 1 N
D. 2 N
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The correct answer is (A). F = qvB sin(theta). Sin(theta) = sin 0 5 0. The particle would feel the maximum magnetic force if it traveled perpendicularly to the field.
