Practice MCAT Question - Q52 - Answer!
What is the expression for the momentum, p, of a charged particle going through a mass spectrometer?
A. p = qrB
B. p = qmB
C. p = qv2
D. p = qvB
The correct answer is (A). From Fc = FB we get mv2/r = qvB. Momentum is p = mv = qrB.
