MCAT Question A Day - 2/18/14 - Answer!
A ball is thrown vertically upward with an initial velocity of 40.0 meters per second. What will be its velocity after 2.00 seconds?
A. 20.4 m/s
B. 9.80 m/s
C. 49.0 m/s
D. 80.0 m/s
The closest choice to 20 m/s is choice (A).
Want more questions? - Click here to check out our MCAT Question A Day archive
The correct answer is (A). v = v0+ at. Estimate the acceleration due to gravity using a = -g = -9.8 m/s2 ~ -10 m/s2. The velocity is approximately:
v = 40.0 m/s - 10 m/s2 (2s)
= 40m/s - 20m/s = 20m/s
The closest choice to 20 m/s is choice (A).
v = 40.0 m/s - 9.80 m/s2 (2s) = 20.4 m/s
